If a solenoid has a resistance of 5 ohms and carries 0.34 amps when 110 volts at 60 Hz is applied, what is the impedance?

• A. 367 ohms
• B. 350 ohms
• C. 360 ohms
• D. None of the above

Answer: (A)

To determine the impedance of the solenoid, we start with the relationship between voltage, current, resistance, and impedance in an AC circuit. Impedance (Z) can be calculated using the formula:

[ Z = \frac{V}{I} ]

where V is the voltage (110 volts) and I is the current (0.34 amps). By substituting the values into the formula:

[ Z = \frac{110}{0.34} ]

Calculating this gives:

[ Z ≈ 323.53 \text{ ohms} ]

However, since this value is clearly not one of the options listed, we must consider the presence of potential inductive reactance in the solenoid due to its inductance at AC frequencies. The total impedance in a circuit where resistance and inductive reactance coexist can be expressed as:

[ Z = \sqrt{R^2 + X_L^2} ]

Where ( R ) is the resistance (5 ohms) and ( X_L ) is the inductive reactance. The reactance can be calculated using the formula:

[ X_L = 2\pi f L ]

Where ( f ) is the frequency (60 Hz).